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Mistake Clinic

Use counterexamples to expose the model error before repairing arithmetic. Keep real failed attempts; there is no requirement to manufacture a quota of mistakes.

Module-Specific Mistake Radar​

Wrong claimSmall counterexample or diagnosticRepair evidence
Three possible head counts are equally likelyTwo fair flips give counts with weights 1/4,1/2,1/4List atomic outcomes before grouping
Sensitivity equals precisionWorked detector: .9 sensitivity but precision 90/585Label both denominators in a count table
Disjoint positive-probability events are independentTheir intersection is zero, their marginal product positiveTest the product definition
Duplicate evidence gives another likelihood multiplierRepeating the same observation supplies no new eventWrite the likelihood conditional on earlier evidence
A retry cap means a fixed number of trialsFirst-attempt success stops the experimentEnumerate terminal paths and count reached attempts
Sampling without replacement is binomialSix machines, two faults, two draws: variance16/45, not4/9Compare PMFs, not just equal means
Linearity needs independenceEmpty-server indicators are dependent but their expectations still addSum indicator expectations with finite means
Zero covariance proves independenceSymmetric X on[-1,1], Y=X²: covariance zero but deterministic dependenceDistinguish linear association from independence
Density height is point probabilityUniform[0,.1] has density10, point probabilities zeroIntegrate over an interval and check units
Weighted p99 values give overall p9999% at10 ms,1% at500 ms: p99=10 ms,mean14.9 msMix CDFs before taking an inverse
The CLT guarantees an accurate result at n=30Highly skewed finite-variance populations can converge slowlyState assumptions and distinguish limiting from finite-n claims
Duplicating observations reduces uncertaintyThe copied-row average is exactly the original averageKeep covariance terms or use the true sampling unit
Zero observed failures proves zero riskAt p=.1, twenty nonfailures occur with probability .9^20Use a justified interval and disclose assumptions
Nominal95% means exact finite-sample95% coverageWald at n=1,p=.5 has coverage zeroEnumerate counts and compare actual coverage
Faster aggregate mean proves a faster versionLab D reverses direction under equal workloadsStandardize target weights and plan a causal comparison

Practice Mistake Checks​

After practice A, explain why observing a randomly selected head differs from learning that at least one head occurred. After practice B, explain why a retry cap does not determine the number of executed trials. After practice C, show why copied measurements cannot create independent evidence. Use the counterexamples above to check the explanation, then solve a changed case without the table.

For each error record the original claim, the violated assumption, a corrected derivation, and a changed case solved without assistance. Link it to PS1–PS8 in the assessment map. Use the separate solutions after an attempt, and record any help received.

Before advancing, repair critical errors in conditioning, stopping, dependence, coverage, and causal interpretation. Passing an arithmetic check does not waive these requirements.